怎樣計算這條數呢?我弄不清

1
0.5(0.5(0.5(0.5(0.5(0.5(0.5x^2+2)+2)+2)+2)+2)+2)=2
4=0.5(0.5(0.5(0.5(0.5(0.5x^2+2)+2)+2)+2)+2)+2
2=0.5(0.5(0.5(0.5(0.5(0.5x^2+2)+2)+2)+2)+2)
如是者,不斷除0.5,減2,最後

0.5x^2+2=4
2=0.5x^2
4=x^2
x=2

2
0.5(0.5(0.5(0.5(0.5x^3+4)+4)+4)+4)=4
8=0.5(0.5(0.5(0.5x^3+4)+4)+4)+4
4=0.5(0.5(0.5(0.5x^3+4)+4)+4)
如是者,不斷除0.5,減4,最後
8=0.5x^3+4
4=0.5x^3
8=x^3
x=2

我試吓~
1. 0.5(0.5(0.5(0.5(0.5(0.5(0.5x^2+2)+2)+2)+2)+2)+2)=2
(0.5(0.5(0.5(0.5(0.5(0.5x^2+2)+2)+2)+2)+2)+2) = 2 ÷ 0.5
0.5(0.5(0.5(0.5(0.5(0.5x^2+2)+2)+2)+2)+2) = (4-2)÷0.5
.........重覆4次 (不斷拆括或從推斷)
0.5x^2+2 = 4
x^2 = (4-2)÷0.5
x^2 = 4
x=2

2.0.5(0.5(0.5(0.5(0.5x^3+4)+4)+4)+4)=4
(0.5(0.5(0.5(0.5x^3+4)+4)+4)+4) = 4 ÷ 0.5
(0.5(0.5(0.5x^3+4)+4)+4) = (8-4) ÷ 0.5
.......重覆2次 (不斷拆括或從推斷)
0.5x^3+4 = 8
x^3 = (8-4) ÷ 0.5
x^3 + 8
x = 2

我唔知你要既係呢d ~