(1)solution X is prepared by mixing 100.0cm3 of 2.0M Na2SO4(aq) with 50.0 cm3 of 1.0M NaNO3(aq). What is the concentration of Na+(aq) ions in X?
A. 1.5M
B. 1.7M
C. 3.0M
D. 3.3M ( ans: C )
CE Chem pastpaper MC 疑難(1)
2007-03-15 4:02 am
回答 (2)
2007-03-16 3:55 am
✔ 最佳答案
啦~ 你知啦 1mole of Na2SO4 有 2mole Na atom所以 no of mole of Na in Na2SO4 = 0.1x2x2 = 0.4
而 no of mole of Na in NaNO3 = 0.05x1=0.05
加埋就是 0.45 *
溝埋gei mixture 共 150cm3 = 0.15 dm3 *
Concentration = no of mole/volume = 0.45/0.15 = 3.0M
C * 啦。
參考: Chemistry
2007-03-15 7:12 am
係Na2SO4之中..
no of mole of Na+ 係 (100/1000)*2*2
係NaNO3之中
no of mole of Na+ (50/1000)*1
so the contration of Na+
{[ (50/1000)*1]+[ (100/1000)*2*2]}/[(100+50)/1000]
=3M
no of mole of Na+ 係 (100/1000)*2*2
係NaNO3之中
no of mole of Na+ (50/1000)*1
so the contration of Na+
{[ (50/1000)*1]+[ (100/1000)*2*2]}/[(100+50)/1000]
=3M
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