z除v=2...32
z+v=176
z=?
HELP ME !好easy既maths題
2007-03-14 10:54 pm
回答 (2)
2007-03-14 11:01 pm
✔ 最佳答案
z=2v+32z+v=176
2v+32+v=176
3v=144
v=48
z=96+32
z=128
2007-03-14 11:19 pm
first,solve
z divided by v is equal to 2...32
The equation is z/v = 2...32,
therefore solve this equation is z = 2v + 32 -(a)
Put equation (a) into the the another equation
i.e. z + v = 176
( 2v + 32 ) + v = 176
3v + 32 = 176
3v =176 - 32
3v = 144
v = 48
Put v = 48, into equation (a)
i.e. z = 2 ( 48 ) + 32
z =128 ( Answer )
The value of z is 128.
Thx....
z divided by v is equal to 2...32
The equation is z/v = 2...32,
therefore solve this equation is z = 2v + 32 -(a)
Put equation (a) into the the another equation
i.e. z + v = 176
( 2v + 32 ) + v = 176
3v + 32 = 176
3v =176 - 32
3v = 144
v = 48
Put v = 48, into equation (a)
i.e. z = 2 ( 48 ) + 32
z =128 ( Answer )
The value of z is 128.
Thx....
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