數學問題[quadratic equation]

我用^2表示 2次方
[1]
9(2-x/5)^2 =22
9*(4-x)^2 = 22*2^2 = 88
(4-x)^2 = 88/9
4-x = 88^0.5/3 or -88^0.5/3
x = 4 - 88^0.5/3 or 4 + 88^0.5/3
x = 0.87 or 7.13

[2]
(2x-1)^2 = (7x+3)^2
2x-1 = 7x+3
5x = -4
x = -4/5

or
2x-1 = -(7x+3)
9x = -2
x = -2/9

2007-03-12 20:15:20 補充：
[1] 我寫錯了9(2-x/5)^2 =229*(10-x)^2 = 22*5^2 =550(10-x)^2 = 550/9 10 - x = 7.817 or -7.817 x = 2.183 or 17.817

9(2-x/5)=22
2-x/5=22/9
-x/5=(22/9)-2
-x=((22/9)-2)*5
x=-2.22 (cor to 3 sig fig)

(2x-1) = (7x+3)
2x-2 = 7x+3
2x-7x= 3+2
-5x= 5
x=5/(-5)
x=-1
I hope i can help you!!