✔ 最佳答案
1:
1/sin@-sin@/tan^2@=sin@/sin^2@-sin@/(sin^2@/cos^2@)
=sin@/sin^2@-sin@cos^2@/sin^2@
=(sin@-sin@cos^2@)/sin^2@
=sin@(1-cos^2@)/sin^2@
=sin@(sin^2@)/sin^2@
=sin@
2
cos@=7/25
斜邊=25 底邊=7 對邊=開方(25^2-7^2)=24
因cos@=7/25 (>0)
@ lies in quadrant I or IV.
When @ lies in quadrant I, tan@=24/7
when @ lies in quadrant IV, tan@=-24/7 (如果你是中三或以下可以不理會這裏)
(sin@-2cos@)/(sin@+3cos@)=[(sin@-2cos@)/cos@]/[(sin@+3cos@)/cos@]
=(tan@-2)/(tan@-3)
=(24/7-2)/(24/7-3) or = (-24/7-2)/(-24/7-3)
=10/3 or =38/45(如果你是中三或以下可以不理會這裏)
3:
L.H.S.=cos@/tan@+sin@
= cos@/(sin@/cos@)+sin@
=cos@(cos@)/sin@+sin^2@/sin@
=(cos^2@+sin^2@)/sin@
=1/sin@
=R.H.S