~F.2 Maths X1

x - 2y + 4 = 0
x + 4 = 2y
y = x/2 + 2

An equation which is parallel to L is required, so it should be in the form y = x/2 + c, where c is a constant (i.e. any number).

So one of the answers is y = x/2 + 1.

(If you like, you may write down
y = x/2,
y = x/2 + 1,
y = x/2 + 2,
y = x/2 + 3,
y = x/2 - 1,
y = x/2 - 2,
y = x/2 - 3,
and so on.)

x-2y+4=0
2y = x+4
y = (1/2)x + 2

I would like to give you the equation y=(1/2)x+3.
The equation I gave you is the translated graph. It is translated one unit upward.(because the equation is y=[(1/2)x +2]+1). So it must be parallel the straight line.
Actually, you can replace +2 by any number. The new equation is still parallel to the straight line.
(My answer takes a=1/2, b=3)

x-2y+4=0
x+4=2y
(x+4)/2=y
y=1/2x+2
so the slope is 1/2 and y-intercept is 2

you can define any line with slope 1/2 so that it's parallel to L
such as :
y=1/2x

or y=1/2x +1
or y=1/2x+3
or y=1/2x+4
or y=1/2x-1
or y=1/2x-2
...........
any line as this form: y=1/2x+ C, where C is a constant.