simplify the following expressions by using the trigonometric identities
[square root (1-sinθ)(1+sinθ)]/cos^2θ
help.
2007-03-09 6:24 am
回答 (2)
2007-03-09 6:34 am
✔ 最佳答案
(square root (1-sinθ)(1+sinθ)]/cos^2θ square root (1-sinθ)(1+sinθ)]/1-sin^2θ
(1-sinθ)^1/2(1+sinθ)^1/2/)(1-sinθ)(1+sin^θ)
1/sqrt(1-sinθ)(1+sin^θ)
2007-03-08 22:37:29 補充：
following step:1/sqrt(cos^2θ)1/cosθsecθ
參考: 天凱(我自己)
2007-03-09 6:30 am
[square root (1-sinθ)(1+sinθ)]/cos^2θ
= [square root (1- sin^2θ)]/cos^2θ
= [square root (cos^2θ)]/cos^2θ
= cosθ/cos^2θ
= 1/cosθ
= secθ
= [square root (1- sin^2θ)]/cos^2θ
= [square root (cos^2θ)]/cos^2θ
= cosθ/cos^2θ
= 1/cosθ
= secθ
收錄日期: 2021-04-12 18:45:20
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070308000051KK04555