3sinθ-cosθ=0
θ=幾呀
pls比步驟
thx a lot
Maths
2007-03-08 5:22 am
回答 (2)
2007-03-08 1:11 pm
✔ 最佳答案
3sinθ-cosθ=03sinθ=cosθ
sinθ/cosθ=1/3
tanθ=1/3
for θ between 0 and pi : θ=18.435
for θ between 0 and 2pi : θ=180+18.435=198.435
2007-03-08 5:33 am
3sinθ-cosθ=0
3sinθ=cosθ
sinθ/cosθ=1/3
tanθ=1/3 <---因為sinθ/cosθ=tanθ
θ=18.1(corr. to 3 sig.fig)
2007-03-08 18:10:59 補充：
θ=18.4(corr. to 3 sig.fig)
3sinθ=cosθ
sinθ/cosθ=1/3
tanθ=1/3 <---因為sinθ/cosθ=tanθ
θ=18.1(corr. to 3 sig.fig)
2007-03-08 18:10:59 補充：
θ=18.4(corr. to 3 sig.fig)
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070307000051KK03924