1.(x^-1y/x^0y^-2)^2
2.2^-1x2^2y-5/4^-3
Maths
2007-03-08 5:17 am
回答 (1)
2007-03-08 4:23 pm
✔ 最佳答案
1.(x^-1y/x^0y^-2)^2=(y^3)/(x^2)
=(y^6)/(x^2)
2.2^-1x2^2y-5/4^-3
=2^(-1+2y-5)/2^(-6)
=2^(2y-6)/2^(-6)
=2^(2y-6+6)
=2^2y
2007-03-08 08:24:17 補充：
1.(x^-1y/x^0y^-2)^2=[(y^3)/(x^2)]^2=(y^6)/(x^2)
收錄日期: 2021-05-02 14:28:30
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070307000051KK03872