有D多項式GE數唔識做,,希望可以幫幫手!!THANKS~
1.
a)化簡(2x+ 4y^2 -5)+(3x- 2y^2 +8)
b)展開(2x-3)(3x^3 -6x^2 +2)
2.
因式分解多項式:
a)9x^2 - 25y^2
b)8a^3 b^3+125
3.
因式分解a^2 b-4ab+4b。由此,因式分解9b^3 - a^2 b+4b
4.
因式分解a^2 - 8ab + 16b^2。由此,因式分解x^4 - 8x^2 y^2+16y^4
關於多項式GE數....THANKS!
2007-03-08 4:33 am
回答 (2)
2007-03-08 4:40 am
✔ 最佳答案
1a =2x+4y^2 -5+3x- 2y^2 +8
=5x + 6y^2 +3
1b
=6x^4 - 12x^3 +4x -9x^3 + 18x^2 - 6
2007-03-07 20:44:05 補充：
2a = (3x 5y )*(3x - 5y )2b = 2^3 a^3 b^3 5^3
2007-03-10 19:02:39 補充：
3a=b(a^2-4a 4)=b(a-2)^23b=b(9b^2-a^2 4)=b[(3b a)(3b-a) 4]4a=(a-4b)^24b=(x^2-4y^2)^2
2007-03-08 5:13 am
1a:
(2x+4y^2-5)+(3x- 2y^2+8)
=2x+4y^2-5+3x-2y^2+8
=5x+2y^2+3
1b:
(2x-3)(3x^3-6x^2+2)
=6x^4-12x^3+4x-9x^3+18x^2-6
=6x^4-21x^3+18x^2+4x-6
2a:
9x^2-25y^2
=(3x+5y)(3x-5y)
2b:
8a^3b^3+125
=(2ab)^3+5^3
=(2ab+5)(4a^2b^2-10ab+25)
3a:
a^2b-4ab+4b
=b(a^2-4a+4)
=b(a-2)^2
3b:
9b^3-a^2b+4b
=b(9b^2-a^2+4)
=b[(3b+a)(3b-a)+4]
4a:
a^2-8ab+16b^2
=(a-4b)^2
4b:
x^4-8x^2y^2+16y^4
=(x^2-4y^2)^2
公式:
2a:
x^2-y^2
=(x+y)(x-y)
2b:
x^3+y^3
=(x+y)(x^2-xy+y^2)
x^3-y^3
=(x-y)(x^2+xy+y^2)
3a/b:
ax+ay+az
=a(x+y+z)
3a/b,4a/b
x^2+2xy+y^2
=(x+y)^2
x^2-2xy+y^2
=(x-y)^2
(2x+4y^2-5)+(3x- 2y^2+8)
=2x+4y^2-5+3x-2y^2+8
=5x+2y^2+3
1b:
(2x-3)(3x^3-6x^2+2)
=6x^4-12x^3+4x-9x^3+18x^2-6
=6x^4-21x^3+18x^2+4x-6
2a:
9x^2-25y^2
=(3x+5y)(3x-5y)
2b:
8a^3b^3+125
=(2ab)^3+5^3
=(2ab+5)(4a^2b^2-10ab+25)
3a:
a^2b-4ab+4b
=b(a^2-4a+4)
=b(a-2)^2
3b:
9b^3-a^2b+4b
=b(9b^2-a^2+4)
=b[(3b+a)(3b-a)+4]
4a:
a^2-8ab+16b^2
=(a-4b)^2
4b:
x^4-8x^2y^2+16y^4
=(x^2-4y^2)^2
公式:
2a:
x^2-y^2
=(x+y)(x-y)
2b:
x^3+y^3
=(x+y)(x^2-xy+y^2)
x^3-y^3
=(x-y)(x^2+xy+y^2)
3a/b:
ax+ay+az
=a(x+y+z)
3a/b,4a/b
x^2+2xy+y^2
=(x+y)^2
x^2-2xy+y^2
=(x-y)^2
參考: myself
收錄日期: 2021-04-25 12:52:59
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070307000051KK03569