What is the distance from the point (-1,-3) to the line y=2?
Show the work, please=]!
The answer is square root of 29, but I don't know how to get there
please explain...
Find the distance?
2007-03-07 5:00 pm
回答 (4)
2007-03-07 10:00 pm
✔ 最佳答案
The answer should be 5.Consider a line y = -3, it passes through (-1,-3)
The distance between y = -3 and y = 2 is (2-(-3)) = 5
2007-03-08 2:03 am
How can you calculate the distance between (-1,3) and the line y=2?
The are infinity points on y=2, for which point do you want to calculate?
I can only do this:
On the line y=2, let all the points on the line be (x,2)
The distance between (-1,-3) and (x,2):
{(-1-x)²+[2-(-3)]²}sqrt. (where sqrt. denotes square root)
=[(1+x)²+25]sqrt.
The are infinity points on y=2, for which point do you want to calculate?
I can only do this:
On the line y=2, let all the points on the line be (x,2)
The distance between (-1,-3) and (x,2):
{(-1-x)²+[2-(-3)]²}sqrt. (where sqrt. denotes square root)
=[(1+x)²+25]sqrt.
2007-03-07 11:26 pm
(x + 1)^2 + (y + 3)^2 = 29
(x + 1)^2 = 4
x + 1 = 2 OR x + 1 = -2
x = 1 OR x = -3
Are u sure your answer is correct?
(x + 1)^2 = 4
x + 1 = 2 OR x + 1 = -2
x = 1 OR x = -3
Are u sure your answer is correct?
參考: EASON MENSA
2007-03-07 10:59 pm
Is the distance you mentioned the perpendicular distance?
If so, the answer is 5. If not, I can't tell you. Please state your problem clearly.
If so, the answer is 5. If not, I can't tell you. Please state your problem clearly.
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