easyIQ題
回答 (4)
2007-03-07 1:45 am
✔ 最佳答案
假設足球有x個,籃球有y個,乒乓球有z個.*** x = y + 12 ------(1)
*** z = x + 22 ------(2)
*** z = 2y ------(3)
(2),(3)
x + 22 = 2y ------(4)
(1),(4)
y + 12 +22 = 2y
y = 34
所以，足球有46個，籃球有34個，乒乓球有68個，
學校儲物室共有148個球。
參考: me
2007-03-07 6:00 am
答案是148
2007-03-07 1:40 am
Let x be the value of basketball
So that,
football=x+12
ping pang ball=x+12+22=2x
x+34=2x
x=34
basketball=34
football=46
ping pang ball=68
Total=148
So that,
football=x+12
ping pang ball=x+12+22=2x
x+34=2x
x=34
basketball=34
football=46
ping pang ball=68
Total=148
2007-03-07 1:38 am
設學校儲物室有籃球a個
a+12+22=2a
a+34=2a
a=34
學校儲物室有籃球34個
學校儲物室有足球
34+12
=46
學校儲物室有乒乓球
56+22
=68
2007-03-06 17:39:23 補充：
學校儲物室共有球34 46 68=148個
a+12+22=2a
a+34=2a
a=34
學校儲物室有籃球34個
學校儲物室有足球
34+12
=46
學校儲物室有乒乓球
56+22
=68
2007-03-06 17:39:23 補充：
學校儲物室共有球34 46 68=148個
收錄日期: 2021-04-12 21:30:56
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070306000051KK02176