50(2y/5+y/10)=(y/2-y/5)y-5y
請問y等於幾多？
有一條數學題想問
2007-03-04 6:08 pm
回答 (4)
2007-03-04 6:17 pm
✔ 最佳答案
50[(2y/5)+(y/10)=[(y/2)-(y/5)]y-5y20y+5y=(y²/2)-(y²/5)-5y
250y=5y²-2y²-5y
3y²-255y=0
3y(y-85)=0
y=0 or y-85=0
y=0 or y=85
2007-03-08 7:44 am
50[(2y/5)+(y/10)=[(y/2)-(y/5)]y-5y
20y+5y=(y²/2)-(y²/5)-5y
250y=5y²-2y²-5y
3y²-255y=0
3y(y-85)=0
y=0 or y-85=0
y=0 or y=85
20y+5y=(y²/2)-(y²/5)-5y
250y=5y²-2y²-5y
3y²-255y=0
3y(y-85)=0
y=0 or y-85=0
y=0 or y=85
2007-03-04 10:46 pm
50(2y/5+y/10)=(y/2-y/5)y-5y
20y+5y=(y/2-y/5)y-5y
20y+5y+5y=(y/2-y/5)y-5y+5y
30y/y=(y/2-y/5)y/y
30=(y/2-y/5)x10
30=5y-2y
30=3y
y=10
20y+5y=(y/2-y/5)y-5y
20y+5y+5y=(y/2-y/5)y-5y+5y
30y/y=(y/2-y/5)y/y
30=(y/2-y/5)x10
30=5y-2y
30=3y
y=10
2007-03-04 6:25 pm
50(2y/5+y/10)=(y/2-y/5)y-5y
20y + 5y=y^/2 - y^/5 - 5y
25y=5y^-2y^/10 - 5y
25y + 5y=(5y^ - 2y^)/10
30y=3y^/10
300y=3y^
y^=100
y=10
20y + 5y=y^/2 - y^/5 - 5y
25y=5y^-2y^/10 - 5y
25y + 5y=(5y^ - 2y^)/10
30y=3y^/10
300y=3y^
y^=100
y=10
收錄日期: 2021-04-13 16:11:45
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070304000051KK00965