求下列數式的值
1. 1+ tan 38˚ tan 52 ˚
答案係 2
請問條數點計
請問條數點計
2007-03-03 10:35 pm
回答 (3)
2007-03-03 10:39 pm
✔ 最佳答案
tan 52 ˚ = 1/tan 38˚ therefore
1+ tan 38˚ tan 52 ˚
=1+ tan 38˚ x (1/tan 38˚)
=1+1
=2
2007-03-03 10:40 pm
1 + tan 38˚ tan 52˚
= 1 + tan 38˚ tan (90˚ - 38˚)
= 1 + tan 38˚ (1/tan 38˚) [tan (90˚ - x) = 1/tan x]
= 1 + 1
= 2
2007-03-03 14:41:34 補充：
= 1 + tan 38˚ (1/tan 38˚) [because tan (90˚ - x) = 1/tan x]
= 1 + tan 38˚ tan (90˚ - 38˚)
= 1 + tan 38˚ (1/tan 38˚) [tan (90˚ - x) = 1/tan x]
= 1 + 1
= 2
2007-03-03 14:41:34 補充：
= 1 + tan 38˚ (1/tan 38˚) [because tan (90˚ - x) = 1/tan x]
2007-03-03 10:39 pm
1+ tan 38˚ tan 52 ˚
=1+tan(90-38)tan52
=1+cot52tan52
=1+1
=2
2007-03-03 14:41:27 補充：
cotθ*tanθ=cosθsinθ/sinθcosθ=1
=1+tan(90-38)tan52
=1+cot52tan52
=1+1
=2
2007-03-03 14:41:27 補充：
cotθ*tanθ=cosθsinθ/sinθcosθ=1
收錄日期: 2021-04-12 23:28:49
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070303000051KK02344