送10分題﹕求M的值

2007-03-03 10:29 pm
22+23+24+...+M=1095
請問正整數M的值是多少﹖

回答 (5)

2007-03-03 10:35 pm
✔ 最佳答案
[(1+M)*M]/2 -[(1+21)*21]/2=1095
(1+M)M-(22)(21)=2190
M^2+M-2652=0
M=51 or -52(rejected)

thus,M=51

2007-03-03 14:37:21 補充:
用到的公式:(首項+尾項)*項數除2eg:1+2+3+4+...+N=(1+N)N/210+11+12+13+....N=(1+N)N/2 -(1+9)9/2
2007-03-03 11:34 pm
22+23+24+...+M=1095

(22+M)(M-22+1)/2=1095

(M+22)(M-21)=2190

M²+M-462=2190

M²+M-2652=0

(M-51)(M+52)=0

M=51
參考: 我
2007-03-03 10:37 pm
22+23+24+...+M=1095

(22+M)(M-22+1)/2=1095

(M+22)(M-21)=2190

M²+M-462=2190

M²+M-2652=0

(M-51)(M+52)=0

M=51 or M=-52 (rejected)

Therefore M=51.
參考: me
2007-03-03 10:36 pm
22+23+24+...+M=1095
(22+M)(M-22+1)/2=1095
(M+22)(M-21)=2190
M²+M-462=2190
M²+M-2652=0
(M-51)(M+52)=0
M=51 or M=-52 (rejected)
Therefore M=51.

2007-03-03 14:50:45 補充:
樓下:抄襲連一隻字也不改動......
2007-03-03 10:33 pm
51~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~


收錄日期: 2021-04-23 00:09:25
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070303000051KK02298

檢視 Wayback Machine 備份