http://chingyihouse.linknethost.com/5552.JPG
A ship starts from a poty A and sails 200km in NW direction to place B . She then travels 50km S15度W to place C.
(a) Find the distance AC
(b) Find the bearing of C from A
AMATHS
2007-03-03 3:05 am
回答 (1)
2007-03-03 3:26 am
✔ 最佳答案
(a)AngleCBA=15+45=60
By cosine law,
AC*2=AB*2+BC*2-2BCACcos60
AC*2=200*2+50*2-10000
AC*2=32500
AC=180km
(b)
BC*2=AB*2+AC*2-2(AB)(AC)COSBAC
50*2=200*2+32500-2(180)(200)COSBAC
BAC=13.5度
BEARING OF C FROM A= N(45+13.5)W=N58.5度W
收錄日期: 2021-05-01 09:37:55
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070302000051KK02868