Math problem?
回答 (7)
2007-03-01 1:06 am
✔ 最佳答案
x=1/1010x=1
10x-1=0
x=3/2
2x=3
2x-3=0
(2x-3)(10x-1)
20x^2-32x+3
2007-03-01 9:05 am
(10x - 1) (2x - 3)
20x^2 - 30x - 2x + 3
20x^2 - 32x + 3
20x^2 - 30x - 2x + 3
20x^2 - 32x + 3
2007-03-01 9:09 am
1/10+3/2=16/10=8/5 (sum and product of the roots)
1/10*3/2= 3/20
so the equation is x^2-8/5x+3/20=0
20x^2-32x+3=0
1/10*3/2= 3/20
so the equation is x^2-8/5x+3/20=0
20x^2-32x+3=0
2007-03-01 9:07 am
0 = (x - .1)(x - 1.5)
0 = x^2 - 1.5x - .1x + (.1)(1.5)
0 = x^2 - 1.6x +.15
If you want integer coefficients, multiply through by 20...
0 = 20x^2 - 32x +3
By the way, there are more than one quadradic equations that have those as solutions. In fact, there are infinitely many. Just multiply through by any number you'd like, and you'll get a new quadratic that has your solutions.
0 = x^2 - 1.5x - .1x + (.1)(1.5)
0 = x^2 - 1.6x +.15
If you want integer coefficients, multiply through by 20...
0 = 20x^2 - 32x +3
By the way, there are more than one quadradic equations that have those as solutions. In fact, there are infinitely many. Just multiply through by any number you'd like, and you'll get a new quadratic that has your solutions.
2007-03-01 9:08 am
y= (x+1/10) (x+3/2)
which is=
y= x^2 + 8/5x+ 3/20
which is=
y= x^2 + 8/5x+ 3/20
2007-03-01 9:05 am
Read you math book and pay attention in class
2007-03-01 9:04 am
pay attention in class.
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