數學題(中一)

1. 6(d-bx)=12x
d-bx=12x
d=12x+bx
x=d/(12+b)
2. (ax+b)/c=dx
ax+b=cdx
ax-cdx= -b
x= -b/(a-cd)
=b/cd-a
3. x/a+x/b=1
(bx+ax)/ab=1
bx+ax=ab
x=ab/(a+b)

1. 6(d-bx)=12x
d-bx=2x
d=x(2+b)
x=d/2+b

2. (ax+b)/c=dx
ax+b=dxc
dxc-ax=b
x(dc-a)=b
x=b/dc-a

3. x/a+x/b=1
x(b+a)/ab=1
x=ab/b+a




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1. 6(d-bx)=12x
6d-6bx=12x
6d=12x+6bx
6d=x(12+6b)
x=6d/(12+6b)

2. (ax+b)/c=dx
ax+b=dxc
ax-dxc= -b
x(a-dc)= -b
x = -b/(a-dc)

3. x/a+x/b=1
bx+ax = ab
x(b+a)=ab
x=ab / (b+a)

(1)
6(d-bx)=12x
6d-6bx=12x
6b=12x-6bx
6b=6(2x-bx)
b=2x-bx
x(2-b)=b
x=b/(2-b)

(2)
(ax+b)/c=dx
ax+b=dcx
ax-dcx=-b
x(a-cd)=-b
x=-b/(a-cd)

(3)
x/a+x/b=1
ab(x/a+x/b)=ab*1
bx+ax=ab
x(a+b)=ab
x=ab/(a+b)

1.

6 (d - bx) = 12x
d - bx = 2x
d = 2x + bx
d = x (2 + b)
x = d / (2 + b)

2.
(ax + b) / c = dx
ax + b = cdx
b = cdx – ax
b = (cd – a) x
x = b / (cd – a)

3.
x / a + x / b = 1
(bx + ax) / ab = 1
bx + ax = ab
x (b + a) = ab
x = ab / (b + a)