送10分題﹕求θ的值

2007-02-28 3:38 am


求θ的值,取值至小數點後兩個位。

回答 (9)

2007-02-28 10:33 pm
✔ 最佳答案
Let the opposite side of θ be AB, and the side of 15 cm be BC.

AB^2 = AC^2+BC^2 - 2AB.AC cos θ

12^2 = 14^2 + 15^2 - 2(14)(15)cos θ

144 = 196 + 225 - 420 cos θ

420cosθ = 277

cosθ = 277 / 420

θ=48.74 (corr. to 2 d.p.)
2007-03-03 8:21 am
..............................................................
參考: Me!!!!!!!!!!
2007-03-01 1:48 am
I don't know !
2007-03-01 12:58 am
用餘弦定理就可以計出(你可以在課本上找到公式)
2007-02-28 3:50 am

圖片參考:http://i150.photobucket.com/albums/s112/charlesyim/SSSSS.jpg

Let the opposite side of θ be AB, and the side of 15 cm be BC.
AB²=AC²+BC²-2AB.AC cos θ
12²=14²+15²-2(14)(15)cos θ
144=196+225-375 cos θ
375 cos θ=277
cos θ=277/375
θ=52.747 (nearest to 3 decimal numbers)

2007-02-28 3:47 am
cosθ=(14^2+15^2-12^2)/(2*14*15)

cosθ=277/420

θ=48.74度

2007-02-27 20:44:29 補充:
用了餘弦定理~~
2007-02-28 3:47 am
唔明你幅圖
2007-02-28 3:44 am
23.58度
2007-02-28 3:41 am
SORRY!!我唔明白!!


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