這裡有3題數,你們睇下啦!!
1.144r2-96r+16
2.-s2-2st-t2
3.25t3-70t2+49t
註:r2=r的二次方,t3=t的三次方,etc.
Hope you help me!! THX!! ^-^
初中數學 - factorization
2007-02-28 2:16 am
回答 (2)
2007-02-28 2:33 am
✔ 最佳答案
(1)144r²-96r+16
=16(9r²-6r+1)
=16[(3r)²-2(3r)(1)+(1)²]
=16(3r-1)²
(2)
-s²-2st-t²
=-(s²+2st+t²)
= -(s+t)²
(3)
25t³-70t²+49t
=t(25t²-70t+49)
=t[(5t)²-2(5t)(7)+(7)²]
=t(5t-7)²
2007-02-28 2:30 am
1.144r2 – 96r +16
= (12r)2 – 2(12r)(4) + (-4)2
= (12r-4)2
2.–s2 -2st – t2
= -[(s)2 + 2(s)(t) +(t)2 ]
= -(s+t)2
3.25t3 – 70t2 + 49t
= t ( 25t2 -70t + 49)
= t [(5t)2 – 2(5t)(7) + (-7)2]
= t (5t – 7)2
所有後尾的"2"都是指2次方或者3次方
= (12r)2 – 2(12r)(4) + (-4)2
= (12r-4)2
2.–s2 -2st – t2
= -[(s)2 + 2(s)(t) +(t)2 ]
= -(s+t)2
3.25t3 – 70t2 + 49t
= t ( 25t2 -70t + 49)
= t [(5t)2 – 2(5t)(7) + (-7)2]
= t (5t – 7)2
所有後尾的"2"都是指2次方或者3次方
收錄日期: 2021-04-12 23:28:39
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