再次有數唔識啦

2007-02-28 12:27 am
如果你地睇唔明既可以同我講~希望你地明白...

simplify:
logx+logx^2

logx^3-log√x

4logx+log√x^3

log^3√a-log^8√a^2

logb+logb^2 / logb^5

log(1/a) / 2loga

log√a / log√a-loga

log√y-logy / 2logy

4log√y+logy^3 / logy^2

logxy+5logx

logab^2+log(b/a) / 4logb

3log√ab-logb^(3/2) / loga^7

回答 (2)

2007-02-28 12:50 am
✔ 最佳答案
logx+logx^2 = logx + 2 logx = 3 logx

logx^3-log√x = 3 logx - 1/2 logx = 5/2 logx

4logx+log√x^3 = 4 logx + 3/2 logx = 11/2 logx

log^3√a-log^8√a^2 = 1/3 loga - 2/8 loga = 1/12 loga

logb+logb^2 / logb^5 = logb + 2 logb / 5 logb = logb + 2/5

log(1/a) / 2loga = -loga / 2loga = -1/2

log√a / log√a-loga = 1 - loga

log√y-logy / 2logy = 1/2 logy - 1/2

4log√y+logy^3 / logy^2 = 2 logy + 3 logy / 2 logy = 2 logy + 3/2

logxy+5logx = logx + logy + 5 logx = 6 logx + logy

logab^2+log(b/a) / 4logb = loga + 2 logb + ( logb - loga ) / 4 logb
= [4 loga logb + 8 (logb)^2 + logb - loga] / 4 logb

3log√ab-logb^(3/2) / loga^7 = 3/2 loga + 3 logb - 3/2 logb / 7loga
= [21/2 (loga)^2 + 21 loga logb - 3/2 logb] / 7 loga
2007-02-28 12:41 am
logx+logx^2
=logx+2logx
=3logx

logx^3-log√x
=3logx-1/2logx
=2.5logx

4logx+log√x^3
=4logx+3/2logx
=5.5logx


收錄日期: 2021-04-12 23:24:48
原文連結 [永久失效]:
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