1.(3/5)^x = 27/125
2. (4^x)(3^x) = 144
*please show the process, thanks.
f.2 Maths x2
2007-02-27 4:12 am
回答 (4)
2007-02-27 4:21 am
✔ 最佳答案
1.(3/5)^x = 27/125
(3/5)^x = (3/5)^3
x = 3
2.
(4^x)(3^x) = 144
12^x = 144
12^x = 12^2
x = 2
參考: EASON MENSA
2007-03-01 2:16 am
好答案
2007-02-27 5:15 am
1.(3/5)^x = 27/125
(3/5)^x = 3^3 / 5^3
(3/5)^x = (3/5)^3
so x = 3
2.(4^x)(3^x) = 144
12^x = 144
so x = 2
(3/5)^x = 3^3 / 5^3
(3/5)^x = (3/5)^3
so x = 3
2.(4^x)(3^x) = 144
12^x = 144
so x = 2
2007-02-27 4:20 am
1.(3/5)^x = 27/125
(3/5)^x = (3*3*3)/(5*5*5)
(3/5)^x = (3/5)*(3/5)*(3/5)
(3/5)^x = (3/5)^3
x=3
2. (4^x)(3^x) = 144
(4^x)(3^x) = 3*3*4*4
(4^x)(3^x) = (4^2)*(3^2)
x=2
(3/5)^x = (3*3*3)/(5*5*5)
(3/5)^x = (3/5)*(3/5)*(3/5)
(3/5)^x = (3/5)^3
x=3
2. (4^x)(3^x) = 144
(4^x)(3^x) = 3*3*4*4
(4^x)(3^x) = (4^2)*(3^2)
x=2
參考: me
收錄日期: 2021-04-12 22:13:01
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