4(mn-2n)^2+(m-2n)^2
THX~~
5識計呀~~f.2數
2007-02-26 3:19 am
回答 (3)
2007-02-26 4:08 am
✔ 最佳答案
4(mn-2n)^2+(m-2n)^2=4(mn-2n)(mn-2n)+(m-2n)(m-2n)
=4(m^2n^2)+(m^2+4n^2)
=4m^24n^2+16n^2+m^2+4n^2
=4m^44n^2+20n^2
=4n^2(m4+5)
參考: myself
2007-02-26 3:32 am
4(mn-2n)^2+(m-2n)^2
=4(m^2n^2+2(mn)(-2n)+4n^2)+(m^2+2(m)(-2n)+4n^2)
=4m^2n^2-16mn^2+16n^2+m^2-4mn+4n^2
=4m^2n^2-(16m-20)n^2+m^2-4mn
=(4n^2-1)m^2-(16m-20)n^2-4mn
=4(m^2n^2+2(mn)(-2n)+4n^2)+(m^2+2(m)(-2n)+4n^2)
=4m^2n^2-16mn^2+16n^2+m^2-4mn+4n^2
=4m^2n^2-(16m-20)n^2+m^2-4mn
=(4n^2-1)m^2-(16m-20)n^2-4mn
參考: MAY BE THIS
2007-02-26 3:26 am
4(mn-2n)^2+(m-2n)^2
=4(m^2)(n^2)-16m(n^2)+8(n^2)+(m^2)-4mn+4(n^2)
=4(m^2)(n^2)-16m(n^2)+8(n^2)+(m^2)-4mn+4(n^2)
收錄日期: 2021-05-03 04:46:09
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https://hk.answers.yahoo.com/question/index?qid=20070225000051KK04827