五角形內角的總和是多少?

2007-02-25 5:50 pm
五角形內角的總和是多少?

回答 (5)

2007-02-25 5:53 pm
✔ 最佳答案
=(n-2)*180
= (5-2)*180
=540
2007-02-25 6:50 pm
=180(n-2) (angle sum of polygon)
=180(5-2)
=180*3
=540(度)
2007-02-25 6:20 pm
You can use the formula 180(n-2) where n = number of vertices of a polygon.

In that case, a pentagon has 5 vertices and hence the sum of its internal angles = 180(5-2) = 540 degrees.

You may interpret the formula as the number of non-overlapping triangles of a polygon that can be formed by joining the same vertex and every adjacent side. For a polygon with n vertices, there are n sides and there are 2 sides (i.e. the side with the fixed vertex as an endpoint) that cannot be formed a triangle with the fixed vertex. Then, (n-2) such triangles can be constructed. As we know the sum of all internal angles of a triangle is 180 degrees, and hence the formula follows.
2007-02-25 5:57 pm
你可以利用以下公式幫助你計算不同形狀的內角和:
(n-2)*180度

由於今次是要計算五角形的內角 總和,
所以(5-2)*180度=540度
2007-02-25 5:56 pm
五角形內角的總和是:
(5-2)*180
=3*180
=540(度)

using formula:(n-2)*180

2007-02-26 13:06:18 補充:
by myself knowledge


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