(1/√2)sinx + (1/√2)cosx <-------
= sin(π/4)sinx + cos(π/4)cosx
sin(π/4) = (√2)/2
但這裡不是1/√2嗎
收錄日期: 2021-04-23 00:13:20
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070221000051KK03985