2. The error in measuring time by Suki's watch is 0.0005%, and by Alan's watch is 0.5s per day.
a) Find the maximum absolute error in Suki's watch per day.
b) Find the relative error in measuring time by Alan's watch.
c) Find the percentage error in measuring time by Alan's watch.(Correct the answer to 3
significant figures.)
Answer:
2a) 0.864s
b) 1/172800
c) 0.000579%
我唔知過程點計
F.2 Approximation and Errors(2)
2007-02-20 7:46 pm
回答 (1)
2007-02-20 10:12 pm
✔ 最佳答案
a. 1day=24 hours=24*60 mins=24*60*60seconds= 86400 seconds
maximum absolute error = maximum error*2
maximum absolute error = 0.0005%*2*86400
=0.864seconds
b. relative error=0.5/86400
=1/172800
c. 1/172800*100%=0.0005787%
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