Maths

2^(2x+2)=9(2^x)-2
2^(2x)．4=9(2^x)-2
Let y=2^x
4y^2=9y-2
4y^2-9y+2=0
(4y-1)(y-2)=0
y=1/4 or y=2
2^x=1/4 or 2^x=2
x=-2 or x=1

2^(2x+2)=9‧2^x-2
2^(2x+2)=3^2‧2^x-2
2^(2x+1)=3^2‧2^(x-1)-1
1=3^2‧2^(x-1)-2^(2x+1)
1=2^(2x-1)‧(3^2-2^2)
2^(2x-1)=1/5
(2x-1)log2=log(1/5)
X=0.611(corr.to.3 sig.fig.)
我唔知ans.是什麼，但希望幫到你吧！

2^(2x+2) = 9．2^x - 2

2^(2x)．2^2=9．2^x - 2

4．2^(2x)-9．2^x+2=0

(4*2^x-1)(2^x-2)=0

2^x=1/4 or 2^x=2

x1=-2 or x2=1

2x+2 x
2 = 9‧2 - 2

2x 2 x
2 ‧2 =9‧2 - 2

2x x 2
2 - 9‧2 = -2 ÷2

x x
2 ( 2 - 9‧1 ) = - 0.5

x x
2 ( 2 - 9 ) = - 0.5

x x
2 -9 = - 0.5 ÷2


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2x+2 x
2 = 9．2 - 2

2x 2 x
2 ‧2 =9‧2 - 2

2 x 2x
2 - 2 = 9. 2 ÷ 2


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