10 marks

2007-02-14 2:29 am

我想問一條數....

A,B 2個數的H.C.F=2x3
A,B 2個數的L.C.M=2x 3的二次方x 5的二次方
AxB=N N=?

唔該~急要~

回答 (5)

2007-02-14 2:33 am

✔ 最佳答案

AxB = N =A'xB'

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2007-02-14 8:30 am

因為
A,B 2個數的H.C.F=2*3
A,B 2個數的L.C.M=2*(3^2)*(5^2)
所以
A*B
=N
=H.C.F.*L.C.M.
=2*3*2*(3^2)*(5^2)
=2700

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2007-02-14 3:10 am

A=6的倍數,因數:1,2,3,6

B=2,3,5的倍數

Therefore,

符合條件只有66x180,

即N=11880

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2007-02-14 2:38 am

11880

2007-02-13 18:39:44 補充：
N=11880

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2007-02-14 2:34 am

AXB = N = HCF * LCM = 2x3 x (2x3^2)x 5^2 = (2x3x5)^2

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