圖片參考:
http://www.ugrad.math.ubc.ca/coursedoc/math101/notes/applications/onedisk.gif
When the curve of y = √(r^2-x^2) revolves around the x-axis, it generates a sphere with radius r.
Volume
=π∫[from -r to r] (√(r^2-x^2))^2 dx
=π∫[from -r to r] (r^2-x^2) dx
=π(r^2x-x^3/3)[from r to -r]
=π(r^3-r^3/3+r^3-r^3/3)
=4/3πr^3
NOTE: A continuous function f(x) with positive images in interval [a,b], revolving around the x-axis, the volume is
π∫[from a to b] f(x)^2 dx
2007-02-13 17:14:42 補充:
應是=π(r^2x-x^3/3)[from -r to r]
2007-02-13 17:19:47 補充:
冇可能﹐我幅圖點會係你畫???我講下點解個積分範圍是-r到r因為我們是用x軸上方的曲線去繞個x軸形成一個球體。而這條曲線的兩端點為(-r,0),(r,0)不過都係要學微積分先明裡面個0的運算