F.2 maths(1 question)

(3^2x*27^x+4)/(3^2x-1)
=3^2x*3^3(x+4)/(3^2x-1)
=3^(2x+3(x+4))/(3^2x-1)
=3^(2x+3X+12)/(3^2x-1)
=3^(5x+12)/(3^2x-1)
=3^(5x+12-(2x-1))
=3^(5x+12-2x+1)
=3^(3x+13)

2007-02-12 23:18:31 補充：
remember:To multiply terms with the same base, add the exponents.To divide terms with the same base, subtract the exponents. When a product has an exponent, each factor is raised to that power. A number with a negative exponent equals its reciprocal with a positive exponent.

(32x)(27 x+4) / 32x-1
= (32x)((33) x+4) / 32x-1
= (32x)(33x+12) / 32x-1
= 32x + 3x+12 – (2x-1)
= 33x+13