1. 8^ 2x+1 / 4^ x+1
2.(3^2x)(27^ x+4) / 3^ 2x-1
3.(2*5^n)^2 + 25^n / 5^n
*please show the process, thanks!
F.2 Maths
2007-02-13 5:43 am
回答 (2)
2007-02-13 5:49 am
✔ 最佳答案
(1)8^(2x+1)/4^(x+1)
=2^[3(2x+1)]/2^[2(x+1)]
=2^[(6x+3)-(2x+2)]
=2^(4x+1)
(2)
[3^(2x)][27^(x+4)]/[3^(2x-1)]
=[3^(2x)][3^3(x+4)]/[3^(2x-1)]
=3^[2x+(x+4)-(2x-1)]
=3^(x+5)
(3)
[2(5^n)]^2+(25^n/5^n)
=4(5^2n)+5^n
2007-02-13 5:50 am
1) 8^2x+1/4^x+1
=4^2(2x+1)/4^x+1
=4^4x+4-x+1
=4^3x+5
=4^2(2x+1)/4^x+1
=4^4x+4-x+1
=4^3x+5
收錄日期: 2021-04-23 00:11:24
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070212000051KK04494