我有一條maths唔係好識計,你們教我點計啦~~
1.ax-a-x+1
幫幫我啦!! ^_^
f.2數學-factorization
2007-02-11 7:23 pm
回答 (4)
2007-02-11 7:26 pm
✔ 最佳答案
ax-a-x+1=a(x-1) -(x-1)
= (a-1)(x-1)
because -(x-1)=-x+1
if we change to this factor
then the whole factorization will have common factor (x-1)
抽common factor就完成~
2007-02-11 7:52 pm
ax-a-x+1
=a(x-1)-(x-1)
=(a-1)(x-1)
留意-號
because 負
負得正，所
以-x+1 應該
變成-(x-1)
=a(x-1)-(x-1)
=(a-1)(x-1)
留意-號
because 負
負得正，所
以-x+1 應該
變成-(x-1)
參考: me
2007-02-11 7:31 pm
ax-a-x+1
=a(x-1)-(x-1)
=(a-1)(x-1)
=a(x-1)-(x-1)
=(a-1)(x-1)
2007-02-11 7:26 pm
ax-a-x+1
=a(x+1)-(x+1)
=(x+1)(a-1)
=a(x+1)-(x+1)
=(x+1)(a-1)
收錄日期: 2021-04-12 23:28:57
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070211000051KK01163