解方程
5y-y的二次方=4
解方程5y-y的二次方=4
2007-02-11 6:10 am
回答 (7)
2007-02-11 6:12 am
✔ 最佳答案
5y-y2次=40=y2次-5y+4
0=(y-4)(y-1)
y=4 or 1
2007-02-11 10:00 pm
0=y2次-5y+4
0=(y-4)(y-1)
y=4 or 1
0=(y-4)(y-1)
y=4 or 1
2007-02-11 7:15 am
5y-y的二次方=4
5y-y(5y-y)=4
4y(4y)=4
4y^2=4
y^2=1
y=1
5y-y(5y-y)=4
4y(4y)=4
4y^2=4
y^2=1
y=1
2007-02-11 6:18 am
(5y-2)^2=4
25Y^2-10Y+4=4
25y^2-10y=0
y(25y-10)=0
y=0 or 25y-10=0
or 25Y=10
or y=10/25>>>2/5
25Y^2-10Y+4=4
25y^2-10y=0
y(25y-10)=0
y=0 or 25y-10=0
or 25Y=10
or y=10/25>>>2/5
2007-02-11 6:17 am
(5y-y)2次=4
5y-y=2
4y=2
y=0.5
緊記係括號5y-y,唔係你好易計左5y-y二次,咁就永遠都計唔到
5y-y=2
4y=2
y=0.5
緊記係括號5y-y,唔係你好易計左5y-y二次,咁就永遠都計唔到
2007-02-11 6:14 am
5y-y^2=4
-y^2+5y-4=0
y^2-5y+4=0
(y-4)(y-1)=0
所以，y=4,1
-y^2+5y-4=0
y^2-5y+4=0
(y-4)(y-1)=0
所以，y=4,1
2007-02-11 6:14 am
5y-y^2=4
y^2-5y+4=0
(y-1)(y-4)=0
y=1 or y=4
y^2-5y+4=0
(y-1)(y-4)=0
y=1 or y=4
收錄日期: 2021-04-12 21:13:46
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https://hk.answers.yahoo.com/question/index?qid=20070210000051KK04746