0=freeter
^=2次方
－=over
1) 1-sin^0 1-cos^0
(－－－－)(－－－－)
ｓｉｎ＾０ ｃｏｓ＾０
2) 1-sin0 cos0 tan0
列式+答案 thx!!!
中四數學(三角)10分!!唔該急用
2007-02-10 10:04 pm
回答 (1)
2007-02-11 4:33 am
✔ 最佳答案
1((1-sin^2θ)/sin^2θ)((1-cos^2θ)/cos^2θ)
=(cos^2θ)(sin^2θ)/(sin^2θ)(cos^2θ)
=1
2
1-sin θ cos θ tan θ
=1-sin θ cos θ (sin θ/cos θ)
=1-sin^2 θ
=cos^2 θ
收錄日期: 2021-04-25 16:51:09
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070210000051KK01997