Maths

0.083333....=0.08+0.003333...

0.08=8/100
0.003333...=3/900
(for any decimal no which repeat itself, the denominator is usually 9, therefore 1/9=0.1111..., 5/9=0.5555...., if there is a 0 in front of the no. such as 0.03333... then you will need to put a 0 next to the denominator 9 , therefore 0.03333...=3/90, for how many 0 there in front of the no, put the same no of 0 next to 9 in the denominator)

therefore,

8/100+3/900=75/900=1/12

2007-02-09 23:01:04 補充：
If you have something like 0.030303... try 3/99. Actually you can play around with different combination of 9 and 0 in the denominator, you will get a lot of intersting but well ordered decimal no. Have fun.

0.0833333333.....
= (0.0833333333...x 100) / 100
= 8.33333.... / 100
= (8.333333.... x 3) / ( 100 x 3)
= 25 / 300
= 1 / 12

0.08333333333333...

=0.33333333....... - 0.25

=1/3-1/4

=(4-3)/12

=1/12

1
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60

但我唔知過程, 我靠經常用計算機.
sorry