數學問題(Secondery)

In the figure,OABC is a rectangle of perimeter 12 units and OC =(二份一)OA.Find the coordinates of A,B and C.
OA+AB+BC+CO=12
2(OA+OC)=12
3OA=12
OA=4
OC=2
SO the coordinates of A,B and C is
A(4,0)
B(4,2)
C(0,2)

2007-02-07 15:19:50 補充：
你唔好再畫個圖搶分啦Guttvennnnnnnnn

2007-02-07 15:22:11 補充：
不過上面是A在X軸如果A在Y軸則A(0,4)B(2,4)C(2,0)

2007-02-07 16:03:04 補充：
點可能有8個可能性呀OC =(二份一)OA bor你x同y肯定計錯佐啦而且照傳統OABC 是A黏著個O的O是原點若果不是的話冇限個可能性啦所以只是得2個可能性朋友﹐今回你係做錯佐架啦

2007-02-07 16:18:13 補充：
諗錯了添﹐原來你講0岩﹐A可以是在負數個邊﹐B又可以選正負我講錯了(不過你個x,y坐標都是計錯)所以還有6個可能性A(4,0)B(4,-2)C(0,-2)ORA(-4,0)B(-4,-2)C(0,-2)ORA(-4,0)B(-4,2)C(0,2)ORA(0,4)B(-2,4)C(-2,0)OR A(0,-4)B(-2,-4)C(-2,0)ORA(0,-4)B(2,-4)C(2,0)

Where is the figure?