二元一次方程..pls help

If 2x^(2m-3n+2) + 3y^(1/4m-2n+6)=7 is a linear equation in two unknowns x and y, find the values of m and n.
linear equation means ax+by+c=0
So the index of x and y are 1
2m-3n+2=1...(1)
(1/4)m-2n+6=1...(2)
from (2) m=4(2n-5)
sub into (1)
8(2n-5)-3n+2=1
16n-40-3n+2=1
13n=39
n=3
m=4(2n-5)=4

2007-02-06 16:38:25 補充：
2m = -1 + 3(3) = 8m=4 AR

2007-02-06 17:08:03 補充：
linear equation in two unknowns ax+by+c=0 中的a,b,c是常數例子:x+2y+3=03x-4y+5=07x+2y-9=14 (因為14可以轉去左手邊)即7x+2y-23=0為何x同y的指數一定要係1因為x或y的指數不是1的時候不能畫成一條直線如x^2+y^2=1 是一個圓y-x^3=0 是一條曲線所以linear equation in two unknowns 中文叫二元一次方程

2007-02-07 02:30:26 補充：
2x^(2m-3n+2) + 3y^(1/4m-2n+6)=7轉換可得2x^(2m-3n+2) + 3y^(1/4m-2n+6)-7=0你對番ax+by+c=0 來看 c 就等於-7所以我們不用理個7﹐因為他已經滿足了linear equation 的條件反而次方數個到要是1即2m-3n+2=1,1/4m-2n+6=1