更新1:
1^(2k+1)=
maths
回答 (3)
2007-02-06 4:14 am
✔ 最佳答案
Assume k is a integer, therefore 2k is an even number-1^2k=1
Therefore
-1^2k+1= 1+1 =2
2007-02-06 4:57 am
-1^(2k+1)= -1
-1^(2k)+ 1= 2
1^(2k+1)= 1
-1^(2k)+ 1= 2
1^(2k+1)= 1
2007-02-06 4:12 am
-1^2k+1= ((-1)^2)^k+1=2
個ans應該係咁~~
2007-02-05 21:35:44 補充：
但係..如果唔係(-1)^2k..係-1^2kge話..個ans會有唔同..(-1)^2k=1-1^2k=-1
個ans應該係咁~~
2007-02-05 21:35:44 補充：
但係..如果唔係(-1)^2k..係-1^2kge話..個ans會有唔同..(-1)^2k=1-1^2k=-1
收錄日期: 2021-05-03 01:20:37
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070205000051KK03538