2 ZnS + 3O2 → 2ZnO + 2SO2 ,
2ZnO + C → 2Zn + CO2
Suppose 48.6 g of zinc oxide are reduced with carbon.
1)what is the mass of zinc obtained?
2)what is the mass of C used for the reduction?
f4 chemistry question
2007-02-04 2:13 am
回答 (2)
2007-02-04 3:18 am
✔ 最佳答案
1)what is the mass of zinc obtained?= 48.6 / (65.4 + 16) x 65.4
= 39.05 g
2)what is the mass of C used for the reduction?
= 12 x 48.6 / (65.4 + 16) / 2
= 3.58 g
2007-02-05 5:37 am
1) Mass of Zn in ZnO=[48.6 x 65.4/(65.4+16)]g=39.047g
2) Since carbon is oxidized to form carbon dioxide,
therefore the mole ratio of carbon to oxygen=1 : 2.
Mass of oxygen in ZnO=(48.6 - 39.047)g=9.553g
So, mass of carbon used=(9.553/2)g=4.776g
2) Since carbon is oxidized to form carbon dioxide,
therefore the mole ratio of carbon to oxygen=1 : 2.
Mass of oxygen in ZnO=(48.6 - 39.047)g=9.553g
So, mass of carbon used=(9.553/2)g=4.776g
收錄日期: 2021-04-12 18:38:15
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