8500x(1-5%)^t=7000 求t

2007-02-01 5:37 am
8500x(1-5%)^t=7000 求t

回答 (5)

2007-02-01 5:42 am
✔ 最佳答案
8500x(1-5%)^t=7000
(95%)^t= 70/85
t log(0.95)= log( 70/85)
t= log(70/85) / log( 0.95)
t=3.7852 cor. to 4 d. p.
2007-02-01 6:33 am
8500x(1-5%)^t=7000
0.95^t=0.8235
t=4

2007-01-31 22:33:27 補充:
t=3.8
2007-02-01 5:45 am
8500 x (1 - 0.05)^t = 7000
0.95^t = 7000 / 8500
0.95^t = 0.8235
t log 0.95 = log 0.8235
t = (log 0.8235) / (log 0.95)
t = 3.7852 (to 4 decimal places)
2007-02-01 5:44 am
8500x(1-5%)^t=7000
(0.95)^t = 7000/8500
0.95^t = 14/17
log 0.95^t = log 14/17
t log 0.95 = log 14/17
t = (log14/17)/log 0.95
t = 3.785 (4s.f.)
2007-02-01 5:43 am
8500 x (0.95)^t = 7000
0.95^t= (7000/8500)
0.95^t= 14/17
t log 0.95 = log(14/17)
t= log(14/17)/log 0.95
t= 35017/9251


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