PQRS is a straight line, intersecting two equal circles, centres A and B.
PS is parallel to AB.
Let AM and BN be perpendicular to PS.
Prove that(i)AM=BN(ii)PQ=R S
更新1:
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Maths Geometry F.3 Homework
2007-02-01 5:23 am
Quick---hand in tomorrow!!!Try your best to answer.
PQRS is a straight line, intersecting two equal circles, centres A and B.
PS is parallel to AB.
Let AM and BN be perpendicular to PS.
Prove that(i)AM=BN(ii)PQ=R S
PQRS is a straight line, intersecting two equal circles, centres A and B.
PS is parallel to AB.
Let AM and BN be perpendicular to PS.
Prove that(i)AM=BN(ii)PQ=R S
回答 (1)
2007-02-01 5:46 am
✔ 最佳答案
∠AMQ = 90 ∠MAB = 90
∠ABN = 90
∠BNR = 90
AMNB is a rectangle and AM=BN
AM=BN
AQ=BS
∠AMQ = ∠BNS = 90
ΔAMQ=ΔBNS (R.H.S)
therefore MQ=NS
similarly PM=RN
therefore PQ=RS
收錄日期: 2021-04-25 16:37:05
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