2) log@(3x=1)=4
p.s.# = 底係3
@=底係2
更新1:
i 'm sorry for 1 mistake. :P 2) log@(3x=1)=4 [@=底係2]
更新2:
extremely sorry呀...我想打 (3x+1),,,成日都打左係= !! XD
更新3:
Mr.Kwok 你可唔可以教我點樣打3次方同2次方果d呀?? (唔係用^3 or ^2 ...呢d符號代表wor*)
f.4 maths (about log)
回答 (3)
2007-01-29 6:29 am
✔ 最佳答案
1) log3(4x-1)=3 (4x-1)=33=27
4x=28
x=7
2) log2(3x=1)=4
3x-1=24=16
3x=17
x=17/3
2007-01-29 6:05 pm
1....
(4x-1)=3^3=27
4x=28
x=7
2.
3x-1=24=16
3x=17
x=17/3
2007-02-05 12:17:31 補充：
good ans.
(4x-1)=3^3=27
4x=28
x=7
2.
3x-1=24=16
3x=17
x=17/3
2007-02-05 12:17:31 補充：
good ans.
2007-01-29 6:32 am
1)log#(4X-1)=3
log(4x-1)/log3=3
log(4x-1)=3log3
log(4x-1)=log3^3
4x-1=27
x=7
2)log@(3x-1)=4
log(3x-1)/log2=4
log(3x-1)=4log2
log(3x-1)=log2^4
3x-1=16
x=17/3
p.s. log@X=k
2^k=x
log2^k=logx
klog2=logx
k=logx/log2
therefore log@x=logx/log2
log(4x-1)/log3=3
log(4x-1)=3log3
log(4x-1)=log3^3
4x-1=27
x=7
2)log@(3x-1)=4
log(3x-1)/log2=4
log(3x-1)=4log2
log(3x-1)=log2^4
3x-1=16
x=17/3
p.s. log@X=k
2^k=x
log2^k=logx
klog2=logx
k=logx/log2
therefore log@x=logx/log2
參考: me
收錄日期: 2021-04-25 16:41:40
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070128000051KK04941