一條証明 1= 2 既式 知道點解ma?=]

b(a - b) = (a + b)(a - b)
↓
b = a + b

由於a=b, 所以變左兩邊除0, undefined

再加上, 就算真係arrive到 b=2b,
只會draw到 b=0 既conclusion
而唔可以兩邊除b然後話 1=2

b(a - b) = (a + b)(a - b)
b = a + b
because a=b
a-b=0
we cannot use 0 to divide anything

a = 1 b = 1
1 = 1
1x1 = 1x1
1x1-1x1 = 1x1-1x1
1(1-1) = (1+1)(1-1) <-明明一邊係b,另一邊點會變左a+b,雖然答案都係0
1 = 1+1 <-點解b會變左等於a+b
1 = 2x1 <-1個b,冇啦啦變左等於2b
1 = 2
照你咁計 a(a-b) = (a-b)(a-b) 咁a係咪等於(a-b) 係咪等於0 ??

p.s 十年前讀到中三冇讀,未學過E種數理,麻煩你教下我

As b(a-b) =(a+b)(a-b) is because (a-b)=0
It is incorrect to conclud that b=a+b as well as 1=2, Okay?

a=b
咁點解b=a+b??

2007-01-27 00:20:56 補充：
b(a - b) = (a b)(a - b)↓ba-b²=a²-b²b²-b²=b²-b²