F4----Chemistry

a) CH4(g) + 2O2 (g) --> CO2 (g) + 2H2O (l)

b) For water: use blue cobalt chloride paper. Water will turn the paper pink.

For CO2: The simple one is to collect the gas, light up a splint, the gas will distinguish it. A better one is that carbon dioxide turns lime water milky. Collect the gas and prepare calcium hydroxide solution. The gas bubbled into the solution will turn it milky.

c)Turn the mass of the compounds into number of moles. You need the molar mass of each compound. I'm doing it briefly here since I don't have a calculator with me. M(CH4) = 12+4 = 16g/mol. M(CO2) = 12+16*2 = 44g/mol. Divide mass by molar mass gives number of moles. So #mol of CH4 = 20/16 = 1.25mol and for CO2 = 80/44=1.81mol.

%efficiency is just divide the no of mol of product (CO2) by the reactant (CH4), since carbon has a 1-1 ratio in the reactant and product:

*I'm not sure why but I could not get a reasonable answer. The no of moles of carbon produced is more than that of the reactant!?

1.3CH4 + 5O2 ---> CO2+ 6H2O+ 2CO + Energy

2.Products to be tested ---> CO2. Collect the gas given off, blow the gas through Lime Water. If CO2 is present Lime Water should turn into a milky white colour because of precipitation of CaCO3.
Product to be tested ---> Water.
Test 1. Testing the boiling point. water has boiling point of 100 degrees
Test 2. water will turn anhudrous copper sulphate from white to blue hydrated copper sulphate (heat released)
Test 3. turn anhydrous cobalt chloride paper from blue to pink.
3. Moles
Balance Equation
3CH4 + 5O2 ---> CO2+ 6H2O+ 2CO
mole of CH4 = 20/16 = 1.25
1.25 mole of CH4, Mole ratio CO2 3:1
1.25/3 mole of CO2 should have Mass of 18.3333
Answer should be right but cant answer your question. Maybe your question is wrong,
If you meant 8.0g of CO2 the answer should be 43.6%
Hope this will help you