中三數學...................
淨做B)
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中三數學................
2007-01-26 1:14 am
回答 (4)
2007-01-26 1:29 am
✔ 最佳答案
(b)MR
=√(25^2-20^2)
=√225
=15 cm
PR=2MR=30 cm
QR
=√(PR^2-PQ^2)
=√(30^2-24^2)
=√324
=18 cm
2007-01-26 2:49 am
(b)
MR
=√(25^2-20^2)
=√225
=15 cm
PR=2MR=30 cm
QR
=√(PR^2-PQ^2)
=√(30^2-24^2)
=√324
=18 cm
MR
=√(25^2-20^2)
=√225
=15 cm
PR=2MR=30 cm
QR
=√(PR^2-PQ^2)
=√(30^2-24^2)
=√324
=18 cm
2007-01-26 1:32 am
you will get the answer 15 cm in part a)
i.e. MR = 15cm
b) PM = MR (長方形特性/rectanglar properties)
所以 PM = 15cm, PR = 30cm
在三角形 PQR 裡,
PR^2 = PQ^2 + QR^2 (畢氏定理)
30^2 = 24^2 + QR^2
900 = 576 + QR^2
QR^2 = 324
QR = 18
所以QR 是18 cm
i.e. MR = 15cm
b) PM = MR (長方形特性/rectanglar properties)
所以 PM = 15cm, PR = 30cm
在三角形 PQR 裡,
PR^2 = PQ^2 + QR^2 (畢氏定理)
30^2 = 24^2 + QR^2
900 = 576 + QR^2
QR^2 = 324
QR = 18
所以QR 是18 cm
2007-01-26 1:31 am
you will get the answer 15 cm in part a)
i.e. MR = 15cm
b) PM = MR (長方形特性/rectanglar properties)
所以 PM = 15cm, PR = 30cm
在三角形 PQR 裡,
PR^2 = PQ^2 + QR^2 (畢氏定理)
30^2 = 24^2 + QR^2
900 = 576 + QR^2
QR^2 = 324
QR = 18
所以QR 是18 cm
i.e. MR = 15cm
b) PM = MR (長方形特性/rectanglar properties)
所以 PM = 15cm, PR = 30cm
在三角形 PQR 裡,
PR^2 = PQ^2 + QR^2 (畢氏定理)
30^2 = 24^2 + QR^2
900 = 576 + QR^2
QR^2 = 324
QR = 18
所以QR 是18 cm
參考: my calculation knowledge
收錄日期: 2021-04-12 21:31:13
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070125000051KK02248