因式分解
a^2-2am+m^2+a^2y-m^2y
a^2y即是a的二次乘y
m^2y即是m的二次乘y
因式分解a^2-2am+m^2+a^2y-m^2y
2007-01-24 9:03 pm
回答 (1)
2007-01-24 10:15 pm
✔ 最佳答案
a2 - 2am + m2 + a2y - m2y= a2 - 2(a)(m) + m2 + y(a2 - m2)
= (a - m)2 + y(a - m)(a + m)
【根據恆等式 A2-B2 = (A-b)(A+B)】
【根據恆等式 (A-B)2 = A2-2AB+B2】
= (a - m)[(a - m) + y(a + m)]
= (a - m)[a - m + ay + my]
或
= (a - m)[a(y+1) + m(y-1)]
收錄日期: 2021-04-12 15:58:05
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070124000051KK01151