f4..maths
回答 (3)
2007-01-22 6:30 am
✔ 最佳答案
已知x隨y及z聯變。當y=3及z=4時,X=60。求Y=4及z=5時x的值由於已知「 x 隨 y 及 z 聯變」，
設 x = kyz 而 k 是常數 ... (#)
代 y = 3, z = 4, x = 60 至 (#)
60 = k(3)(4)
k = 5
所以 (#) 變成 x = 5yz ... (##)
代 y = 4, z = 5 至 (##)
x = 5(4)(5)
x = 100
所以當 y = 4, z = 5 時 x = 100。
2007-01-22 9:21 pm
設 x = knz ( k 是常數 )
代入 n = 3, z = 4, x = 60, 求k的值
60 = k(3)(4)k = 5
--> x = 5nz
代入 n= 4, z = 5 , 求x的值
x = 5(4)(5)
x = 100
--> n= 4, z = 5 時 x = 100
2007-01-22 13:21:52 補充：
不是n是y
代入 n = 3, z = 4, x = 60, 求k的值
60 = k(3)(4)k = 5
--> x = 5nz
代入 n= 4, z = 5 , 求x的值
x = 5(4)(5)
x = 100
--> n= 4, z = 5 時 x = 100
2007-01-22 13:21:52 補充：
不是n是y
2007-01-22 7:50 pm
設 x = kyz ( k 是常數 )
代入 y = 3, z = 4, x = 60, 求k的值
60 = k(3)(4)k = 5
--> x = 5yz
代入 y = 4, z = 5 , 求x的值
x = 5(4)(5)
x = 100
--> y = 4, z = 5 時 x = 100
代入 y = 3, z = 4, x = 60, 求k的值
60 = k(3)(4)k = 5
--> x = 5yz
代入 y = 4, z = 5 , 求x的值
x = 5(4)(5)
x = 100
--> y = 4, z = 5 時 x = 100
參考: my knowledge
收錄日期: 2021-04-13 15:30:12
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070121000051KK05171