因式分解題

2007-01-21 5:40 am
f(x)=(2x-1)(3x²+5x-2)-7x-14

已知道(3x²+5x-2)=(x+2)(3x-1)

回答 (3)

2007-01-21 5:45 am
✔ 最佳答案
f(x)
=(2x-1)(3x²+5x-2)-7x-14
=(2x-1)(x+2)(3x-1)- 7(x+2)
=(x+2)((2x-1)(3x-1)- 7)
= (x+2)(6x²-5x-6)
= (x+2)(2x-3)(3x+2)
2007-01-21 8:27 pm
f(x)=(2x-1)(3x²+5x-2)-7x-14
(3x²+5x-2)=(x+2)(3x-1)

f(x)=(2x-1)(3x²+5x-2)-7x-14
=(2x-1)(3x²+5x-2)-7(x+2)
=(2x-1)(x+2)(3x-1)-7(x+2)
=(x+2)(6x^2-5x+1-7)
=(x+2)(6x^2-5x-6)
=(x+2)(2x-3)(3x+2)
2007-01-21 5:48 am
f(x)=(2x-1)(3x²+5x-2)-7x-14
(3x²+5x-2)=(x+2)(3x-1)

f(x)=(2x-1)(3x²+5x-2)-7x-14
=(2x-1)(3x²+5x-2)-7(x+2)
=(2x-1)(x+2)(3x-1)-7(x+2)
=(x+2)(6x^2-5x+1-7)
=(x+2)(6x^2-5x-6)
=(x+2)(2x-3)(3x+2)

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