應該點計???
答案是39
更新1:
仲有一題 1∕4 y+(y+2)×2=49
MATHS.....................
回答 (2)
2007-01-20 11:58 pm
✔ 最佳答案
(y+1)×19∕20= y-1(y+1)×19= (y-1)×20
19y+19=20y-20
y=39
2007-01-20 15:59:49 補充：
1∕4 y+(y+2)×2=49 (1/4)y+2y+4=49(9/4)y=45y=45*4/9y=20
2007-01-20 11:59 pm
先multiply 20
==>(y+1)x19=20y-20
拆左左邊個括號
==>19y+19=20y-20
兩邊加20
==>19y+39=20y
兩邊減19y
==>39=y
==>(y+1)x19=20y-20
拆左左邊個括號
==>19y+19=20y-20
兩邊加20
==>19y+39=20y
兩邊減19y
==>39=y
收錄日期: 2021-04-23 16:33:52
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070120000051KK02620