(9c-3c^2)(3c+6c^2-6c)
約簡
數學方程式
2007-01-19 5:34 am
回答 (5)
2007-01-19 5:39 am
✔ 最佳答案
(9c-3c2)(3c+6c2-6c)=(9c-3c2)(6c2-3c)
=[3c(3)-3c(c)][3c(2c)-3c(1)]
=3c*3c*(3-c)(2c-1)
=9c2(3-c)(2c-1)
咁得未？
參考: me
2007-01-29 5:52 am
要ｓｉｍｐｌｉｆｙ
2007-01-20 12:00 am
(9c-3c^2)(3c+6c^2-6c)
=27c^2 + 54c^3 - 54c^3 - 9c^3 - 18c^4 + 18c^3
=-18c^4 + 63c^3 -27c^2
=27c^2 + 54c^3 - 54c^3 - 9c^3 - 18c^4 + 18c^3
=-18c^4 + 63c^3 -27c^2
2007-01-19 5:53 am
(9c-3c^2)(3c+6c^2-6c)
=27c^2 + 54c^3 - 54c^3 - 9c^3 - 18c^4 + 18c^3
=-18c^4 + 63c^3 -27c^2
Is my ans. correct???
=27c^2 + 54c^3 - 54c^3 - 9c^3 - 18c^4 + 18c^3
=-18c^4 + 63c^3 -27c^2
Is my ans. correct???
參考: Myself
2007-01-19 5:38 am
(9c - 3c²)(3c + 6c² - 6c)
= [3c(3 - c)] [3c(1 + 2c - 2)]
= 9c²(3 - c)(2c - 1)
= [3c(3 - c)] [3c(1 + 2c - 2)]
= 9c²(3 - c)(2c - 1)
收錄日期: 2021-04-12 21:32:49
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